Limit image size, fixes #4464.

[librarian.git] / src / librarian / embeds / mathml.py

diff --git a/src/librarian/embeds/mathml.py b/src/librarian/embeds/mathml.py
index 801c213..f633fc4 100644 (file)
--- a/src/librarian/embeds/mathml.py
+++ b/src/librarian/embeds/mathml.py
@@ -1,8 +1,7 @@
-# -*- coding: utf-8 -*-
-from __future__ import unicode_literals
-
+# This file is part of Librarian, licensed under GNU Affero GPLv3 or later.
+# Copyright © Fundacja Wolne Lektury. See NOTICE for more information.
+#

 from lxml import etree
 from lxml import etree

-import six

 from librarian import get_resource
 from . import TreeEmbed, create_embed, downgrades_to
 
 from librarian import get_resource
 from . import TreeEmbed, create_embed, downgrades_to
 


@@ -12,19 +11,19 @@ class MathML(TreeEmbed):
     def to_latex(self):
         """
         >>> print(MathML(etree.fromstring(
     def to_latex(self):
         """
         >>> print(MathML(etree.fromstring(

-                '<mat>a &lt; b</mat>'
-            )).to_latex().data.strip())
+        ...     '<mat>a &lt; b</mat>'
+        ... )).to_latex().data.strip())

         a < b
 
         >>> print(MathML(etree.fromstring(
         a < b
 
         >>> print(MathML(etree.fromstring(

-                '<mat>&lt; &amp; &amp;lt; &#65;</mat>'
-            )).to_latex().data.strip())
+        ...     '<mat>&lt; &amp; &amp;lt; &#65;</mat>'
+        ... )).to_latex().data.strip())

         < & &lt; A
 
         """
         xslt = etree.parse(get_resource('res/embeds/mathml/mathml2latex.xslt'))
         output = self.tree.xslt(xslt)
         < & &lt; A
 
         """
         xslt = etree.parse(get_resource('res/embeds/mathml/mathml2latex.xslt'))
         output = self.tree.xslt(xslt)

-        text = six.text_type(output)
+        text = str(output)

         # Workaround for entities being preserved in output.
         # But there should be a better way.
         text = text.replace('&lt;', '<').replace('&amp;', '&')
         # Workaround for entities being preserved in output.
         # But there should be a better way.
         text = text.replace('&lt;', '<').replace('&amp;', '&')