Canvas list API fix: removing unnecessary lists if all items extracted
authorAleksander Łukasz <aleksander.lukasz@nowoczesnapolska.org.pl>
Wed, 10 Jul 2013 11:24:36 +0000 (13:24 +0200)
committerAleksander Łukasz <aleksander.lukasz@nowoczesnapolska.org.pl>
Wed, 10 Jul 2013 11:24:36 +0000 (13:24 +0200)
modules/documentCanvas/canvas/canvas.js
modules/documentCanvas/canvas/canvas.test3.js

index a274fa4..d883835 100644 (file)
@@ -196,13 +196,17 @@ $.extend(Canvas.prototype.list, {
             last = item;
         });
 
-        var secondList = documentElement.DocumentNodeElement.create({tag: 'div', klass:'list-items'}, this);
+        if(list.children().length === 0)
+            list.detach();
 
-        last.after(secondList);
+        if(succeedingItems.length > 0) {
+            var secondList = documentElement.DocumentNodeElement.create({tag: 'div', klass:'list-items'}, this);
+            last.after(secondList);
 
-        succeedingItems.forEach(function(item) {
-            secondList.append(item);
-        });
+            succeedingItems.forEach(function(item) {
+                secondList.append(item);
+            });
+        }
     }
 });
 
index 9a549df..597fec2 100644 (file)
@@ -485,6 +485,27 @@ describe('Canvas', function() {
                 expect(list2.children().length).to.equal(1, 'second list has one child');
                 expect(list2.children()[0].children()[0].getText()).to.equal('3', 'first item of the second list is a last item of the original list');
             });
+
+            it('removes list if all its items are extracted', function() {
+                var c = canvas.fromXML('\
+                    <section>\
+                        <div class="list.items">\
+                            <div class="item">some item</div>\
+                        </div>\
+                    </section>'),
+                    list = c.doc().children()[0],
+                    item = list.children()[0];
+
+                c.list.extractItems({element1: item, element2: item});
+
+                var section = c.doc(),
+                    list1 = section.children()[0],
+                    oldItem1 = section.children()[1],
+                    oldItem2 = section.children()[2],
+                    list2 = section.children()[3];
+
+                expect(section.children().length).to.equal(1, 'section contains one child');
+            });
         });
 
     });